Gay lussac worksheet
Gay-Lussac's Law
Problems #1 - 10
Ten Examples
KMT & Gas Laws Menu
Problem #1: A 30.0 L sample of nitrogen inside a rigid, metal container at 20.0 °C is placed inside an oven whose temperature is 50.0 °C. The pressure inside the container at 20.0 °C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 50.0 °C?
Solution:
P1 P2 ––– = ––– T1 T2
3.00 x ––– = ––– 293 323 Solution technique: cross-multiply and divide.
x = 3.31 atm (to three sig figs)
Note: you will see set ups (especially in gas laws) that simply omit all the units in the answer. If you do that on a homework difficulty or test, you may get a deduction. It's not laziness on the part of the person writing the solution, it's simply assuming the reader knows what the units are and how they cancel out to depart the final unit.
Many times, you (as the student) are not allowed that luxury.
Problem #2: Determine the pressure alter when a constant volume of gas at 1.00 atm is heated
NAME_________________________________ CLASS___________________ DATE____________
1. Which variable is plotted on the graph's vertical axis? __________________
2. Which variable is plotted on the graph's horizontal axis? ________________
3. What is the pressure in kilopascals? _________________
4. The red plunger is used to exert pressure on the gas molecules in which colored area? _____________.
5. Finalize the table below as you view the animated gas lab.
6. What complete you predict the temperature will be when the volume is 5.5? ______________________
7. Sketch the completed temperature-volume graph to the right:
8. Click on "Effect of changing temperature on volume." Describe what is used to increase the temperature._________________
9. Sketch the completed volume-temperature graph to the right:
10. Compose the formula equation for Charles and Gay-Lussac's Law. ___________________________
11. Write the equation for Charles and Gay-Lussac's Law in words. _____________________________
12. In the animated gas lab, the unit of temperature is _________________.
13. What are the units of volume used in th
Gay-Lussac's Law
Gay-Lussac's Law, also known as the pressure-temperature law, is one of the gas laws discovered by the French chemist Joseph Louis Gay-Lussac in 1802. This law describes the relationship between the pressure and temperature of a gas at constant volume. The law can be stated as:
Pf / Tf = Pi / Ti
Where Pf and Tf are the final pressure and temperature of the gas, and Pi and Ti are the initial pressure and temperature of the gas, respectively.
Explanation of Gay-Lussac's Law
Gay-Lussac's Law states that the pressure of a given amount of gas held at unchanging volume is directly proportional to the Kelvintemperature. This means that as the temperature of a gas increases, so does its pressure, and vice versa. Mathematically, this can be expressed as P / T = k, where P is the pressure, T is the temperature in Kelvin, and k is a constant.
Application of Gay-Lussac's Law
This rule is particularly important in comprehending the behavior of gases in various real-world scenarios. For instance, it helps in predicting how changes in temperature will influence the pressure of a gas in a sealed container, such as a gas cylinder or a balloon. It also forms th